2/3^(x)-1=1/3^(x)-5

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Solution for 2/3^(x)-1=1/3^(x)-5 equation: 



2/3^(x)-1=1/3^(x)-5

We move all terms to the left:

2/3^(x)-1-(1/3^(x)-5)=0



Domain of the equation: 3^x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3^x-5)!=0

x∈R



We get rid of parentheses

2/3^x-1/3^x+5-1=0

We multiply all the terms by the denominator


5*3^x-1*3^x+2-1=0

We add all the numbers together, and all the variables

5*3^x-1*3^x+1=0

Wy multiply elements

15x-3x+1=0

We add all the numbers together, and all the variables

12x+1=0

We move all terms containing x to the left, all other terms to the right

12x=-1

x=-1/12

x=-1/12

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